NTSE Stage 2 SAT 2014 Question Paper

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Question : 46 of 100

Marks: +1, -0

In △ABC,

\ov{\XY}

is parallel to

\ov{\AB}

and divides the triangle into the two parts of equal area. Then the

{\AX}/{\AB}

equals

${√2+1}/1$
${2-√2}/2$
${2+√2}/2$
${√2-1}/1$

Solution:

{\BX^2}/{\AX^2}=1/2

⇒

{\BX}/{\AB}=1/√2

⇒

{\AX}/{\AB}={2-√2}/2

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