NTSE Stage 2 SAT 2014 Question Paper

Question : 37 of 100

Marks: +1, -0

Consider two conducing plates A and B, between which the potential difference is 5 V, plate A being at a higher potential. A proton and an electron are released at plates A and B respectively. The two particles then move towards the opposite plates - the proton to plate B and the electron to plate A. Which one will have a larger velocity when they reach their respective destination plates ?

Both will have the same velocity.
The electron will have the larger velocity.
The proton will have the larger velocity.
N one will be able to reach the destination point.

Validate

Solution:

The electron has less mass as compared to proton. Hence, gain larger velocity. Work = (Charge) (Potential difference)

(\q_\e)(5\V)=1/2\m_\e\V^2_\e

...(i)

(\q_\p)(5\V)=1/2\m_\p\V^2_\p

...(ii)

(\q_\e=\q_\p),(\m_\e<\m_\p)

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