NTSE Stage 2 SAT 2014 Question Paper

Question : 30 of 100

Marks: +1, -0

Two objects, one 4 times as massive as the other, are approaching each other under their mutual gravitational attraction. When the separation between the objects is 100 km, the acceleration of the lighter object is 1m/

\s^{2}

. When the separation between them is 25 km, the acceleration of the heavier object is

1m/ $\s^{2}$
2m/ $\s^{2}$
8m/ $\s^{2}$
4m/ $\s^{2}$

Validate

Solution:

Gravitational force

\F={\G\M_1\M_2}/\R^{2}

{\G(\m)(4\m)}/(100)^{2}=\m(a_1)

...(i)

{\G(\m)(4\m)}/(25)^{2}=(4\m)a_2

...(ii)

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