NTSE Stage 2 MAT 2016 Question Paper

Maximum length of rod which can be fitted in cubical box in Diagonal of cubical box.
∴ Let the diagonal of cubical box is x
To find value x, first we have to calculate diagonal length of any face of box.
In ∆ABD $\mathrm{a}=\sqrt{1^2+1^2}$
$\mathrm{a}=\sqrt{2}\mathrm{m}$
In ∆ABC ${\mathrm{a}}^2+1^2={\mathrm{x}}^2$
∴ $\mathrm{x}=\sqrt{{\left(2\right)}^2+{\left(1\right)}^2}$
$\mathrm{x}=\sqrt{3}\mathrm{m}$