NIMCET 2025 Paper

Let the two-digit number be $10\mathit{a}+\mathit{b}$, where:
- $\mathit{a}=$ tens digit
- $\mathit{b}=$ units digit
- $\mathit{a}\mathit{b}=12$
Possible digit pairs whose product is 12 :
- $\left(2,6\right)⟶$ number $=26$
- $\left(6,2\right)⟶62$
- $\left(3,4\right)⟶34$
- $\left(4,3\right)⟶43$
Now apply the condition:
If 36 is added, the digits interchange.
Test each:
- $26+36=62⟶$ digits swapped ✓
- $34+36=70⟶$ not swap
- $43+36=79⟶$ not swap ×
- $62+36=98⟶$ not swap ×
Only 26 works.