If 8^{x-1}= (\frac{1}{4}) ^x then the value of {1}/{\log _{x+1} 4-\log _{x+1} 5}+ {1}/{\log _{1-x} 4-\log _{1-x} 5} is:

NIMCET 2025 Paper

Section: Mathematics

Question : 48 of 120

Marks: +1, -0

8^{x-1}= (\;{1}/{4}) ^x

then the value of

\;{1}/{\log _{x+1} 4-\log _{x+1} 5}+\;{1}/{\log _{1-x} 4-\log _{1-x} 5}

is:

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