If \alpha and \beta are the two roots of the equation x^2+a x+b=0, (a b \neq 0) then the quadratic equation with roots \frac{1}{\alpha^3+\alpha} \text{ and } \frac{1}{\beta^3+\beta} is:

Correct Answer is : b(b2+1+a2−2b)x2+(a3+a−3ab)x+1=0

b (b^2+1+a^2-2 b) x^2- (a^3+a-3 a b) x+1=0

b (b^2+1+a^2-2 b) x^2+ (a^3+a-3 a b) x+1=0

b (b^2+1+a^2+2 b) x^2- (a^3+a-3 a b) x+1=0

b (b^2+1+a^2+2 b) x^2+ (a^3+a-3 a b) x+1=0

NIMCET 2025 Paper

Section: Mathematics

Question : 39 of 120

Marks: +1, -0

α

and

β

are the two roots of the equation

x^2+a x+b=0, \;\; (a b ≠ 0)

then the quadratic equation with roots

\;{1}/{α^3+α} \;\text " and "\; \;{1}/{β^3+β}

is:

Go to Question:

Prev Question

Next Question