NIMCET 2024 Paper

Section: Mathematics

Question : 40 of 120

Marks: +1, -0

How much work does it take to slide a crate for a distance of 25 m along a loading dock by pulling on it with a 180 N force where the dock is at an angle of

45^{∘}

from the horizontal?

$3.18198 × 10^3 J$
$3.18198 × 10^2 J$
$3.4341 × 10^3 J$
$3.4341 × 10^4 J$

Validate

Solution:

The work done is

\ov{F} ⋅ \ov{d}=|F||d| \cos θ

180 × 25 × \cos 45=3181.98 J

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