NIMCET 2024 Paper

Section: Mathematics

Question : 26 of 120

Marks: +1, -0

Among the given numbers below, the smallest number which will be divided by 9,10 , 15 , and 20 , leaving the remainders

4,5,10

, and 15 respectively, is:

Solution:

The difference between all the remainder from the divisors is 5 , hence the answer should be

\;{\LCM}(9,10,15,20) k-5

\;=180 k-5

There is only one such number 355 .

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