NIMCET 2024 Paper

Section: Mathematics

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Question : 13 of 120

Marks: +1, -0

If

F=40 N,|D|=3 m

, and

θ=60^{∘}

, then the work done by

F

acting from

P

to

Q

is:

$60 {√{ }} 3 J$
120 J
$60 {√{ }} 2 J$
60 J

Solution:

Work done

=|F||D| \cos θ=40 × 3 × \;{1}\/{2}=60

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