NIMCET 2023 Question Paper with solutions

A computer producing factory has only two plants ${\mathrm{T}}_1$ and ${\mathrm{T}}_2$. Plant ${\mathrm{T}}_1$ produces $20\%$ and plant ${\mathrm{T}}_2$ produces $80\%$ of the total computers produced. $7\%$ of computers produced in the factory turn out to be defective. It is known that $\mathrm{P}$ (computer turns out to be defective given that it is produced in plant ${\mathrm{T}}_1$ ) $=10\mathrm{P}$ (computer turns out to be defective given that it is produced in plant ${\mathrm{T}}_2$ ). A computer produced in the factory is randomly selected and it does not turn out to be defective. Then the probability that it is produced in plant ${\mathrm{T}}_2$ is: