NIMCET 2023 Question Paper with solutions

Question : 24 of 120

Marks: +1, -0

An urn contains 5 yellow, 4 black and 3 white balls. 3 balls are drawn at random. The probability that no black ball is selected is:

Solution:

5 {\Y}+4 {\B}+3 {\G}=12

balls
Non black ball

=8

balls

{\P}

(No black ball is selected)

=\;{{ }^8 {\C}_3}/{{ }^{12} {\C}_3}=\;{8 × 7 × 6}/{12 × 11 × 10}=\;{14}/{55} .

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