If the foci of the ellipse \frac{x^2}{25}+\frac{y^2}{b^2}=1 and the hyperbola \frac{x^2}{144}-\frac{y^2}{81}=\frac{1}{25} are coincide, then the value of b^2 is

NIMCET 2022 Question Paper with solutions

Question : 49 of 120

Marks: +1, -0

If the foci of the ellipse

\;{x^2}/{25}+\;{y^2}/{b^2}=1

and the hyperbola

\;{x^2}/{144}-\;{y^2}/{81}=\;{1}/{25}

are coincide, then the value of

b^2

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