For a \in R (the set of all real numbers), a \neq-1, \lim_{n \to \infty} \frac{(1^a+2^a+. . .+n^a)}{(n+1)^{a-1}[(n a+1)+(n a+2)+. . .+(n a+n)]}=\frac{1}{60}. Then one of the values of a is

NIMCET 2022 Question Paper with solutions

Question : 47 of 120

Marks: +1, -0

For

a ∈ R

(the set of all real numbers),

a ≠-1, \lim ↙{n → ∞} \;{(1^a+2^a+. . .+n^a)}/{(n+1)^{a-1}[(n a+1)+(n a+2)+. . .+(n a+n)]}=\;{1}/{60}

. Then one of the values of a is

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