The function {\f}( {\x})=\log ( {\x}+\sqrt{ {\x}^2+1}) is

Correct Answer is : an odd function

neither an even nor an odd function

NIMCET 2022 Question Paper with solutions

Question : 41 of 120

Marks: +1, -0

The function

{\f}( {\x})=\log ( {\x}+√{ {\x}^2+1})

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