If {\D}=|\table 1 , 1 , 1 ; 1 , 2+x , 1 ; 1 , 1 , 2+y|, x \neq 0, y \neq 0 then D is?

Correct Answer is : Divisible by (x+1) and (y+1)

Divisible by ( {\x}+1) and ( {\y}+1)

Divisible by (1+ {\x}) but not (1+ {\y})

NIMCET 2022 Question Paper with solutions

Question : 33 of 120

Marks: +1, -0

{\D}=|\table 1 , 1 , 1 ; 1 , 2+x , 1 ; 1 , 1 , 2+y|, x ≠ 0, y ≠ 0

then

D

is?

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