Correct Answer is : P(A∪B)c=P(Ac)P(Bc)

{\P}( {\B} ∣ {\A})= {\P}( {\B})- {\P}( {\A})

{\P}( {\A}^{ {\c}}- {\B}^{ {\c}})= {\P}( {\A}^{ {\c}})- {\P}( {\B}^{ {\c}})

{\P}( {\A} \cup {\B})^{ {\c}}= {\P}( {\A}^{ {\c}}) {\P}( {\B}^{ {\c}})

NIMCET 2022 Question Paper with solutions

Question : 28 of 120

Marks: +1, -0

0< {\P}( {\A})< 1

and

0< {\P}( {\B})< 1

, and

{\P}( {\A} ∩ {\B})= {\P}( {\A}) {\P}( {\B})

, then

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