Solution of the equation \tan ^{-1} \sqrt{x^2+x}+\sin ^{-1} \sqrt{x^2+x+1}=\frac{\pi}{2} are

NIMCET 2022 Question Paper with solutions

Question : 13 of 120

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Solution of the equation

\tan ^{-1} √{x^2+x}+\sin ^{-1} √{x^2+x+1}=\;{π}/{2}

are

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