NIMCET 2021 Question Paper with solutions

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Question : 5 of 120

Marks: +1, -0

If a variable takes values

0,1,2,3, \....., 50

with frequency

1,{ }^{50} {C}_{2} \...... .{ }^{50} {C}_{50}

then A.M. is

50
25
$2^{50} \/ 50$
51

Solution:

x	f	fx
0	1	0
1	$^50C_1$	$1^50C_1$
2	$^50C_2$	$2^50C_2$
.	.	.
.	.	.
.	.	.

A M={\ ∑ f_{x}}/{\∑f}

A M={0+1 \.{ }^{50} {C}_{1}+2 \.{ }^{50} {C}_{2}+\.... .+50^{50} {C}_{50}}/{1+{ }^{50} {C}_{1}+{ }^{50} {C}_{2}+\....+{ }^{50} {C}_{50}}

={502^{49}}/{2^{50}}

=50/2

=25

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