If the position vector of A and B relative to O be \stackrel{\^}{i}-4 \stackrel{\^}{j}+3 {k^{\^}} and -\stackrel{\^}{i}+2 \stackrel{\^}{j}-\stackrel{\^}{k} respectively then find median through \overrightarrow{{O}} of \\Delta{ABC} is :

-2 \stackrel{\^}{{j}}+2 \stackrel{\^}{{k}}

-\stackrel{\^}{j}+\stackrel{\^}{k}

-{{i^{\^}}}-{{j}}^{\^}+\stackrel{\^}{{k}}

-{{i}}^{\^}-{{j}}^{\^}-\stackrel{\^}{{k}}

NIMCET 2021 Question Paper with solutions

Question : 40 of 120

Marks: +1, -0

If the position vector of

A

and

B

relative to

O

{i}↖{\^}-4 {j}↖{\^}+3 {k↖{\^}}

and

-{i}↖{\^}+2 {j}↖{\^}-{k}↖{\^}

respectively then find median through

{{O}↖{→}}

\Δ{ABC}

is :

Solution:

{OA}↖{→}={i}↖{\^}-4 {j}↖{\^}+3 {k↖{\^}}

{OB}↖{→}=-{i}↖{\^}+2 {j}↖{\^}-{k}↖{\^}

{OC}↖{→}={{OA}↖{→}+{OB}↖{→}}/2

=-{j}↖{\^}+{k}↖{\^}

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