NIMCET 2021 Question Paper with solutions

Question : 30 of 120

Marks: +1, -0

The four geometric means between 2 and 64 are

Solution:

We know that common ratio of

{n}

G.M.
Between

{a}

and

{b}

is,

r=({b}/{a})^{{1}/{n+1}}

r=({64}/{2})^{{1}/{4+1}}

r=2

G_{1}=a r^{1}=2 \× 2=4

G_{2}=a r^{2}=2 \×2^{2}=8

G_{3}=a r^{3}=2 \×2^{3}=16

G_{4}=a r^{4}=2 \×2^{4}=32

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