NIMCET 2020 Question Paper with solutions

Question : 45 of 120

Marks: +1, -0

Angle of elevation of the top of the tower from 3 points (collinear) A, B and C on a road leading to the foot of the tower are 30°, 45° and 60°, respectively. The ratio of AB and BC is

$√3:1$
$√3:2$
1:2
$2:√3$

Validate

Solution:

AB=h(\cot 30°-\cot45°)

=h(√3-1)

BC=h[\cot45°-\cot60°]

=h[1-1/√3]

=h[{√3-1}/√3]

∴ {AB}/{BC}={h[√3-1]}/{h[{√3-1}/√3]}=√3:1

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