If g(x)=\\begin{array}{c}{x^2-X\end\frac{array}{2x},x\neq0;k,x=0 is a continuous function at x = 0, then the value of k is

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NIMCET 2020 Question Paper with solutions

Question : 23 of 120

Marks: +1, -0

g(x)=\{\table {x^2-X}/{2x},x≠0;k,x=0

is a continuous function at x = 0, then the value of k is

Solution:

g(x)=\{\table {x^2-X}/{2x},x≠0;k,x=0

\lim↙{x→0}{x^2-x}/{2x}

\lim↙{x→0}{x-1}/2={0-1}/2

⇒ {-1}/2

then for function to be continuous at x = 0
value of

k={-1}/2

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