NIMCET 2020 Question Paper with solutions

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Question : 21 of 120

Marks: +1, -0

Find

\lim↙{x→0}x^2e^{\sin(1/x)}

1
limit does not exist
infinity
None of these

Solution:

\lim↙{x→0}x^2e^{\sin(1/x)}dx

Since

\sin(1/x)

varies from -1 to1
Therefore

0×e^{-1 \;to\; 1}=0

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