NIMCET 2019 Question Paper with solutions

Question : 46 of 120

Marks: +1, -0

The mean of 5 observation is 5 and their variance is 124. If three of the observations are 1, 2, 6, then the mean deviation from the mean of the data is

Validate

Solution:

Let the numbers are 1,2,6,x,y

\ov{x}={1+2+6+x+y}/5

5={9+x+y}/5

⇒x+y=16

M.D(\ov{x})=\;\;{|1-5|+|2-5|+|6-5|+|x-5|+|y-5|}/{5}

M.D(\ov{x})=\;\;{4+3+1+x+y-10}/{5}

={8+16-10}/5=14/5=2.8

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