If \sum_{i=1}^{n}x_i = 80 and \sum_{i=1}^{n}x_1^2 =400, then a possible value of n among the following is

NIMCET 2019 Question Paper with solutions

Question : 19 of 120

Marks: +1, -0

Σ↙{i=1}↖{n}x_i

= 80 and

Σ↙{i=1}↖{n}x_1^2

=400, then a possible value of n among the following is

Solution:

Given

Σ↙{i=1}↖{n}x_i=80

and

Σ↙{i=1}↖{n}x_1^2=400

We know that.

{Σx^{2}}/{n}>({Σx_{i}}/{n})^{2}

∴\;{400}/{n}>({80}/{n})^{2}

⇒n > 16

∴ Possible value of x is 18.

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