NIMCET 2018 Question Paper with solutions

Question : 54 of 120

Marks: +1, -0

A runs 1

2/3

times as fast as B. If A gives B start of 80 m, how far must the winning post be so that A and B might reach it at the same time?

200 m
400 m
300 m
160 m

Validate

Solution:

A runs 1

2/3

times as fast as B.
Hence, ratio of speed of A. and B = 5 : 3 or we can say A moves 5 m in the same time in which B moves 3 moreHence, A gains 2 m over B by running 5 m.
∴ Required distance =

5/2

× 80 = 200 m

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