NIMCET 2018 Question Paper with solutions

© examsiri.com

Question : 49 of 120

Marks: +1, -0

Slope of two lines

6x^2

- 2xy -

2y^2

= 0 differ by

$5/2$
$7/2$
$7/5$
- 1

Solution:

Let two slopes of lines may be

m_1

and

m_2

∴

m_1+m_2

=

{-2h}/b

=

2/(-2)

= - 1
and

m_1m_2

=

a/b

=

6/(-2)

= - 3
Now ,

(m_1-m_2)^2

=

(m_1+m_2)^2

- 4

m_1m_2

(m_1-m_2)^2

=

(-1)^2

- 4 (-3)
∴

(m_1-m_2)^2

= 1 + 11 = 13

m_1-m_2

=

√{13}

= 3.60 =

7/2

(approx.)

© examsiri.com

Go to Question:

Prev Question

Next Question