NIMCET 2018 Question Paper with solutions

Question : 12 of 120

Marks: +1, -0

9 balls are to be placed in 9 boxes and 5 of the balls cannot fit into 3 small boxes. The number of ways of arranging one ball in each of the boxes is

18720
18270
17280
12780

Validate

Solution:

Given that 5 balls cannot fit in small boxes.
So, we have only 4 balls to arrange in 3 small boxes.
Which can be arranged in

↖{4}C_3

× 3!
Now, we have (6) balls left, which can be arranged in 6! ways.
Hence, the total number of ways

↖{4}C_3

× 3! × 6! = 4 × 6 × 720 = 17280

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