NIMCET 2017 Question Paper with solutions

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Question : 119 of 120

Marks: +1, -0

Differentiate [- log(log x) , x > 1] with respect to x.

${-1}/(xlogx)$
$1/{logx}$
$1/x$
x log x

Solution:

Let y = - log (logx), x > 1
On differentiating both sides, we get

{dy}/{dx}

= -

d/{dx}

(log (log x))
=

1/{logx}

d/{dx}

(log x)
=

{-1}/{logx}

1/x

= -

1/{xlogx}

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