NIMCET 2016 Question Paper with solutions

Question : 56 of 120

Marks: +1, -0

A box contains 2 blue caps, 4 red caps, 5 green caps and 1 yellow cap. If four caps are picked at random, the probability that none of them is green is;

7/99
7/12
5/99
5/12

Validate

Solution:

Total number of outcomes = selection of 4 caps from (2 blue + 4 red + 5 green + 1 yellow) 12 caps

=^12C_4

Favorable number of outcomes

=^7C_4

∴ Required probability

=^7C_4/^12C_4

=7!/{4!3!}/12!/{4!8!}=7!/3!×8!/12!

={8×7×6×5×4}/{12×11×10×9×8}=7/99

Go to Question:

Prev Question

Next Question