NIMCET 2016 Question Paper with solutions

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Question : 54 of 120

Marks: +1, -0

If C is the midpoint of AB and P is any pointoutside AB then;

${PA}↖{-}$ + ${PB}↖{-}$ = 2 ${PC}↖{-}$
${PA}↖{-}$ + ${PB}↖{-}$ = ${PC}↖{-}$
${PA}↖{-}$ + ${PB}↖{-}$ + 2 ${PC}↖{-}$ = 0
${PA}↖{-}$ + ${PB}↖{-}$ + ${PC}↖{-}$ = 0

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