NIMCET 2015 Question Paper with solutions

Question : 61 of 120

Marks: +1, -0

The remainder when

2^{31}

is divided by 5 is;

Solution:

Here.

2^{31}

is divided by 5

2^{31}=2^{30}×2^{1}

=(2^{2})^{15}×2

=(4)^{15}×2

=(-1+5)×2=4×2=8+5=3

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