NIMCET 2015 Question Paper with solutions

37 H means ${\left(00110111\right)}_2$,
17 H means ${\left(00010111\right)}_2,$
Now, we convert 37H, 17H binary number into decimal number
${\left(00110111\right)}_2$, decimal number = ${\left(55\right)}_{10}$
${\left(00010111\right)}_2$, decimal number = ${\left(23\right)}_{10}$
${\left(55\right)}_{10}+{\left(23\right)}_{10}=23)55(2={\left(9\right)}_{10}$
        $46$  or
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         $9$  ${\left(1001\right)}_2$
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${\left(1001\right)}_2$ Hexadecimal = 09, remainder = 09 H
On division of 37H by 17H the remainder is 09H