NIMCET 2014 Question Paper with solutions

Question : 52 of 120

Marks: +1, -0

Four players A B, C and D have to form into two pairs, however, no pair can play together more than seven times in a row A and B have played seven games in a row. C and D have three in a row. C does not to work with A. Who should play with B?

A
D
C
Cannot be determined

Validate

Solution:

It is very clear from the given information that C does not work with A, therefore C should be the partner with B as they can form pairs i.e. AD and C8.
So, according to the question,
Number of possibility for each player is

\table ,A,B,C,D;B,x,x,x,✓;B,x,x,✓,x;C,x,x,x,✓;D,✓,x,x,x

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