NIMCET 2014 Question Paper with solutions

Question : 32 of 120

Marks: +1, -0

If A, B and C is three angles of a ΔABC, whose area is A. Let a, b and c be the sides opposite to the angles A, B andC respectively. If s =

{a+b+c}/2

= 6 , then the product

1/3 s^2

(s - a) (s - b) (s - c) is equal to

Solution:

We have,
s =

{a+b+c}/2

2s = a + b + c ... (i)
and

1/3 s^2

(s - a) (s - b) (s - c)
=

1/3

s [s (s - a) (s - b) (s - c)]
=

1/3 s[Δ^2]

1/3×6×Δ^2

= 2

Δ^2

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