NIMCET 2014 Question Paper with solutions

Total alphabet in English =26
Two words can be selected from 26 alphabet in $\stackrel{26}{}{\mathit{P}}_1$ × $\stackrel{26}{}{\mathit{P}}_1$ ways
Now, next three digits from 0 to 3
i.e. 0,1, 2, 3 are selected.
= $\stackrel{4}{}{\mathit{P}}_1$ × $\stackrel{4}{}{\mathit{P}}_1$ × $\stackrel{4}{}{\mathit{P}}_1$ × $\stackrel{4}{}{\mathit{P}}_1$ = ${\left(\stackrel{4}{}{\mathit{P}}_1\right)}^3$
∴ Password = $\stackrel{26}{}{\mathit{P}}_1$ × $\stackrel{26}{}{\mathit{P}}_1$ × ${\left(\stackrel{4}{}{\mathit{P}}_1\right)}^3$
= ${\left(\stackrel{26}{}{\mathit{P}}_1\right)}^2$ × ${\left(\stackrel{4}{}{\mathit{P}}_1\right)}^3$