NIMCET 2012 Question Paper with solutions

Question : 54 of 120

Marks: +1, -0

In a club, there are certain number of males and females. If 15 females are absent, then number of males will be half of females. If 45 males are absent, then female strength will be 5 times that of males. Number of males actually present is

Validate

Solution:

Let x and y be the certain number of males and females.
Then, by condition,
x =

1/2

(y - 15)
⇒ 2x = y - 15
⇒ 2x - y = - 15 ... (i)
and 5 (x - 45) = y
⇒ 5x - y = 225 ... (ii)
On subtracting Eq. (i) from Eq. (ii), we get
3x = 240 ⇒ x = 80
∴ Number of males = 80

Go to Question:

Prev Question

Next Question