NIMCET 2012 Question Paper with solutions

Question : 29 of 120

Marks: +1, -0

The number of different license plates that can be formed in the format 3 English letters (A ... Z) followed by 4 digits (0? 1, ... 9) with repetitions allowed in letters and digits is equal to

$26^3×10^4$
$26^3+10^4$
36
$26^3$

Validate

Solution:

The number of arrangements of 3 English letterswith repetitions allowed
= 26 . 26 . 26

(26)^3

The number of arrangements of 4 digits with repetition allowed
= 10 . 10 . 10 . 10 =

(10)^4

∴ Required number of different licence plates
=

(26)^3×(10)^4

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