NIMCET 2011 Question Paper with solutions

Given number is $223355888.$
Here, digits are $\left(2,2,3,3,5,5,8,8,8\right)$
Here, add digits are $\left(3,3,5,5\right)$ and even digits are $\left(2,2,8,8,8\right)$
In a nine diqit number, there are four-even position in
which four odd number $\left(3,3,5,5\right)$ can be arranged in $\frac{4!}{2!\times 2!}=6$ and rest of five odd position, five even number
$\left(2,2,8,8\right)$ 8) can be arranged in $\frac{5!}{2!\times 3!}=10$
$\therefore$ Total number of ways $=6\times 10=60$