NIMCET 2009 Question Paper with solutions

Question : 59 of 120

Marks: +1, -0

The sum of the numbers from 1 to 100 , which are not divisible by 3 and 5, is

Solution:

Required sum

=(1+2+. . .+100)-13+6+. . .+99 -(5+10+. . .+100)+(15+30+. . .+90)

=5050-\;{3 × 33 × 34}/{2}-\;{5 × 20 × 21}/{2}+15 × 21

=5050-1683-150+315=2632

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