NIMCET 2009 Question Paper with solutions

Question : 50 of 120

Marks: +1, -0

Computer A takes 3 min to process an input while computer

B

takes 5 min. If computers

A, B

and

C

can process an average of 14 inputs in one

{h}

, how many minutes does computer

C

alone take to process one input?

Solution:

Let

x

min be the time taken by

C

to process one input.
Then,

14=\;{20+12+60/x}/{3}

⇒ \;\; 42=32+\;{60}/{x}

⇒ \;\; \;{60}/{x}=10 ⇒ x=6

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