NIMCET 2009 Question Paper with solutions

Question : 44 of 120

Marks: +1, -0

Find the unit digit of

(13687)^{3265}

Solution:

Power of last digit

7^{2}=7, 7^{2}=9

7^{3} ≈ 3,7^{4}=1

As,

(1368 )^{3265}=(13687)^{816 × 4+1}

Hence, last digit of

(13687)^{3263}

is last digit of

7^{1}=7

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