NIMCET 2009 Question Paper with solutions

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Question : 15 of 120

Marks: +1, -0

The straight lines

\;{x}/{a}-\;{y}/{b}=k

and

\;{x}/{a}+\;{y}/{b}=\;{1}/{k}, k ≠ 0

meet

a parabola
an ellipse
a hyperbola
a circle

Solution:

\;{x}/{a}-\;{y}/{b}=k

and

\;{x}/{a}+\;{y}/{b}=\;{1}/{k}

is jointly satisfied by

(\;{x}/{a}-\;{V}/{b})(\;{x}/{a}+\;{Y}/{b})=(k)(\;{1}/{k})

⇒ \;{x^{2}}/{d^{2}}-\;{y^{'}}/{b^{2}}=1

, which is a hyperbola.

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