NIMCET 2009 Question Paper with solutions

Question : 10 of 120

Marks: +1, -0

How many different path's in the x y -plane are there from (1,3) to (5,6) if a path proceeds one step at a time by going either one step to the right (R) or one step upwards (U)?

35
40
45
None of these

Validate

Solution:

To go from

(1,3)

(5,6)

, total at 7 steps are needed out of which any 4 will be in right and remaining 3 in upward, which will be done in

{ }^{7} C_{4} ×{ }^{3} C_{3}=35

ways

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