NIMCET 2008 Question Paper with solutions

© examsiri.com

Question : 9 of 120

Marks: +1, -0

Suppose a, b, c are in AP with common difference d . Then,

e^{1{/} c}, e^{b{/}{a c}} e^{1{/}a}

are in

AP
GP
HP
None of these

Solution:

Since,

a, b

and

c

are in A P .

⇒2 b=a+c

...(i)
Now, we take

e^{1 {/ }c} ⋅ e^{1 {/ }3}=e^{1 {/ }c+1 \ a} e^{a+c {/ }{ac}}=e^{{2 b}{/ }{d c}}

[from Eq.(i)]

=(e^{b{/}{ac}})^{2}

⇒ e^{1{/}c}, e^{b{/}a c}

and

e^{1 {/ }a}

are in GP.

© examsiri.com

Go to Question:

Prev Question

Next Question