NIMCET 2008 Question Paper with solutions

Question : 67 of 120

Marks: +1, -0

A certain street has 1000 buildings. A sign-maker is contracted to number the houses from 1 to 1000 . How many zeroes will be needed?

Solution:

\;{0}/{↑} 9

cases for two digit numbers.

{}/{↑}{0}/{}{}/{↑} 9 × 10=90

cases
For three digit numbers.

{9}/{↑} {}/{↑} {0}/{} \;\; 9 × 10=90

cases
In 1000 there is

30 {s}

Total

0 =9+90+90+3=192

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