NIMCET 2008 Question Paper with solutions

Question : 24 of 120

Marks: +1, -0

A six faced die is a biased one. It is thrice more likely to show an odd number than to show an even number. It is thrown twice. The probability that the sum of the numbers in the two throws is even, is

Validate

Solution:

P(1)=P(3)=P(5)= {1}/{4}

P(Z)=P(4)=P(6)= {1}/{12}

Now, sum of two odd numbers, and also sum of two even numbers is even, so,

P

(odd, odd)

+P

(even, even)

= {3}/{4} × {3}/{4}+ {1}/{4} × {1}/{4}= {10}/{16}= {5}/{8}

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