NIMCET 2008 Question Paper with solutions

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Question : 101 of 120

Marks: +1, -0

Let

A=11111010

and

B=00001010

be two 8 bit 2 's complement numbers. Their product in 2's complement is

11000100
10011100
10100101
11010101

Solution:

2's complement of

A=00000110

2's complement of

B=11110110

\;\;\;11110110= (246)_{10}

×00000110

────────=(6)_{10}

\;\;\;00000000

11110110

11110110

10111000100=(1476)_{10}

8, bit representation of, 10111000100 is

11000100=(196)_{10}

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