NIFT UG 2019 Question Paper with solutions

Question : 23 of 150

Marks: +1, -0

A shopkeeper sells an article at a loss of

12 \;{1}/{2} \%

. Had he sold an article for

₹ 51.80

more, he would have earned a profit of

6 \% .

The cost profit of an article is

Solution:

Let the CP of the book be

₹ x

.
According to the question.

\;{x ×(100-{25}/{2})}/{100}+51.80=\;{x × 106}/{100}

⇒ \;\; \;{175 x}/{2 × 100}+51.80=\;{x × 106}/{100}

⇒ \;\; \;{x × 175}/{200}+51.80=\;{x × 106}/{100}

⇒ \;\; \;{175 x+10360}/{200}=\;{106 x}/{100}

⇒ \;\; 175 x+10360=2 x × 106

⇒ \;\; 212 x-175 x=10360

⇒ \;\; 37 x=10360

∴ \;\; x=280

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